Bound Volumes
Find the volume of the solid bound by y=8-x, y=6[sqrt(x-1)], x-axis, y-axis, rotating about the x-axis?
using a single integral it is the “shell method”…2π radius height thickness …radius is y {in [0,6] } , height { large x – small x} (8-y) – (y²/36 + 1)], thickness is dy…for 2 integrals use “disc method”..π radius ² thickness…int over [1,2] of {π36[x-1] dx} + int over [2,8] of {π (8-x)² dx}
Handling Bound Volumes
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